Interior: \(C\) is any set then,
\(\dot{C} = \textrm{interior of C} = \underset{S \textrm{ is open} \, \& S \subseteq C}{\bigcup} S\)
Closure: Let \(C \subseteq \mathbb{R}^n\) be any set.
\(\overline{C} = \textrm{closure of C} = \underset{S \textrm{ is closed} \, \& S \supseteq C}{\bigcap} S\)
Boundary \(\partial C = \overline{C}\setminus \dot{C}\).
Interior of a set is an open set since it is an arbitrary union of open sets. In fact it is the largest open set contained in \(C\). Closure of a set is a closed set since it is an arbitrary intersection of closed sets. In fact it is the smallest closed set containing \(C\). It follows that if \(C\) is open, \(\dot{C}=C\) and if \(C\) is closed, then \(\overline{C}=C\). This means that if \(C\) is open, \(\partial C\) contains no point of \(C\) and if \(C\) is closed, all points of \(\partial C\) are points of \(C\).
Local minimum is exactly what the English word says: a point in the domain is a local minimum of the function if there is a neighbourhood in which the function takes values greater than or equal to the value at such a point. That is \(x^* \in S\) is said to be a \(\textbf{local minimum}\) if \(\exists \, r >0\) s.t.
\(f(x^*) \le f(x) \quad \forall x \in B(x^*, r) \cap S\)
Unconstrained minimum and global minimum are the corresponding terms given for the above inequality holding over all of \(\mathbb{R}^n\) or over all of the feasible region respectively. What about constraints while trying to optimize?